To solve this system of equations by elimination, what operation could be used to eliminate the y-variable and find the value of x? 2x β 4y = 6 β3x + 3y = 12
Accepted Solution
A:
2x - 4y = 6 -3x + 3y = 12
In order to find x (first) you need to eliminate y
3( 2x - 4y = 6) 4( -3x + 3y = 12)
6x -12y = 18 -12x +12y = 48
y cancels out and you should now have
6x - 12x = 18 +48 Simplify the equation;
-6x = 66 Divide both sides by - 6 to get x by itself,