You roll a number cube numbered from 1 to 6. What is the probability that the number is 2,6,3,4,or 1
Accepted Solution
A:
[tex] \frac{5 \: = \: number \: of \: favorable \: outcomes}{6 \: = \: number \: of \: possible \: outcomes} [/tex]Since there are 6 possible outcomes, that will become the denominator. In addition, since we are trying to find the probability of rolling 5 numbers out of that 6, 5 would be the numerator.So the answer is, [tex] \frac{5}{6} [/tex]